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16+16t^2/4t=3*5t-6
We move all terms to the left:
16+16t^2/4t-(3*5t-6)=0
Domain of the equation: 4t!=0We get rid of parentheses
t!=0/4
t!=0
t∈R
16t^2/4t-3*5t+6+16=0
We multiply all the terms by the denominator
16t^2-(3*5t)*4t+6*4t+16*4t=0
We add all the numbers together, and all the variables
16t^2-(+3*5t)*4t+6*4t+16*4t=0
We multiply parentheses
16t^2-60t^2+6*4t+16*4t=0
Wy multiply elements
16t^2-60t^2+24t+64t=0
We add all the numbers together, and all the variables
-44t^2+88t=0
a = -44; b = 88; c = 0;
Δ = b2-4ac
Δ = 882-4·(-44)·0
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7744}=88$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(88)-88}{2*-44}=\frac{-176}{-88} =+2 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(88)+88}{2*-44}=\frac{0}{-88} =0 $
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